P. 236(12) 选作题
This problem outlines a proof of the Buckingham pi theorem, which states (roughly speaking) that any complete equation implies an equation in which all variables appear in dimensionless combinations.
(a) Let be measurements of
(primary or
secondary) quantities. Suppose that there is one and only one functional
relationship
(1)
connecting these
measurements and that equation (1) is complete.
Suppose further that there are fundamental units and that each
is decreased by a factor
. Show that there must be a
relationship of the form
. (2)
(As the proof unfolds, it may be helpful to work a particular example that illustrates the general results for which the exercise calls.)
(b) Deduce from equation (2) that
, (3)
where a subscript on
denotes the
partial derivative with respect to the ith argument.
(c) Assuming that , introduce the new
independent variables
,
, (4)
so that
, (5)
where
, (6)
Show that
, (7)
where the subscript on
denotes a
derivative with respect to the kth argument. Show also that all
quantities
have
dimensional exponent unity with respect to the first primary quantity.
(d) Introduce another new set
of independent variables :
, (8)
so that
, (9)
where
, (10)
Show that . Show also that the
quantities
are
dimensionless with respect to the first primary quantity. Thus equation (1) implies equation
(9), a relation involving m-1 quantities that have a dimensional
exponent zero with respect to the first primary quantity.
(e) Show that the above
conclusion remains valid even if some or all of the quantities are zero.
(f) Deduce finally the relation
, (10)
where the quantities are
dimensionless. Noting the change of variables involved, show also that the
are products
of powers of
.
Show that “usually” there will be m-n such dimensionless
products.
REMARK.
Suppose that can be solved
for
and
that the expression for
actually contains
. If one solves for
, then each term in
the resulting expression must be of the same dimension. This result is called
the principle of dimensional homogeneity.
Input by zjzheng